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The number of all possible matrices of order 3 with each entry either 0 or 1 is:

Solution

✅ Correct Option: 4

A matrix of order 3 is a 3×3 matrix with 3 rows and 3 columns.

The matrix has 3 × 3 = 9 entries in total.


Each entry can be either 0 or 1.

This means each of the 9 entries has 2 possible choices.


Using the counting principle, the total number of possible matrices is:

2×2×2×2×2×2×2×2×2=292 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^9


Calculating 292^9:

29=5122^9 = 512

Therefore, the number of all possible matrices of order 3 with each entry either 0 or 1 is 512.

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