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If two dice are rolled 12 times and getting a total greater than 4 is considered as a success, then which of the following statements are correct?

(A) The probability of getting a total greater than 4 in a single throw of the pair of dice is 5/6.

(B) Mean = 10

(C) Variance = 3/5

(D) The probability of getting a total less than or equal to 4 in a single throw of the pair of dice is 1/6.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

When rolling two dice together, success is defined as getting a total greater than 4.

The outcomes where total ≤ 4 are:

Total of 2: (1,1) → 1 way

Total of 3: (1,2), (2,1) → 2 ways

Total of 4: (1,3), (2,2), (3,1) → 3 ways

Total ways to get ≤ 4 = 1 + 2 + 3 = 6 ways


Total possible outcomes when rolling two dice = 6 × 6 = 36

P(total≤4)=636=16P(\text{total} \leq 4) = \frac{6}{36} = \frac{1}{6}

Statement D is correct.

P(total>4)=1−16=56P(\text{total} > 4) = 1 - \frac{1}{6} = \frac{5}{6}

Statement A is correct.


The experiment follows a Binomial Distribution with:

n=12n = 12 (number of trials)

p=56p = \frac{5}{6} (probability of success)

q=1−p=16q = 1 - p = \frac{1}{6} (probability of failure)


Mean = n×pn \times p

Mean = 12×5612 \times \frac{5}{6}

Mean = 1010

Statement B is correct.


Variance = n×p×qn \times p \times q

Variance = 12×56×1612 \times \frac{5}{6} \times \frac{1}{6}

Variance = 12×53612 \times \frac{5}{36}

Variance = 6036=53\frac{60}{36} = \frac{5}{3}

Statement C claims variance = 35\frac{3}{5}, which is incorrect since 53≠35\frac{5}{3} \neq \frac{3}{5}.


Statements (A), (B), and (D) are correct.

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