CUET Mathematics - Match List-I with List-II | List-I | List-II | |---|---| | (A) Integrating factor of xdy - (y + x^2)dx = 0 | (I) x^2 | | (B) Integrating factor of xdy + (2y + x^2)dx = 0 | (II) x^3 | | (C) Integrating factor of (3y - x^2)dx + xdy = 0 | (III) x | | (D) Integrating factor of (y + 3x^2)dx + xdy = 0 | (IV) 1/x | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2025 21 May Shift 2

Calculus

Medium

core

(A) - (IV), (B) - (I), (C) - (II), (D) - (III)

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

(A) - (I), (B) - (II), (C) - (IV), (D) - (III)

(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

✅ Correct Option: 1

Related questions:

30 May Shift 1

The product of order and degree of the differential equation $\left(\frac{d^3y}{dx^3}\right)^3 + x^2y\left(\frac{d^2y}{dx^2}\right)^3 = 2x^5$ is:

19 May Shift 1

Match List-I with List-II

Choose the correct answer from the options given below:

19 May Shift 1

Match List-I with List-II

List-I	List-II
Differential Equation	Order and degree of differential equation
(A) $\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^2 = e^{\frac{dy}{dx}} + 1$	(I) Order = 1, Degree = 2
(B) $\left(\frac{d^2y}{dx^2}\right)^2 + 4\left(\frac{dy}{dx}\right)^3 = e^y - 1$	(II) Order = 2, Degree = 1
(C) $3\left(\frac{dy}{dx}\right) + 4y + e^y = \frac{dx}{dy}$	(III) Order = 2, Degree = 2
(D) $\frac{d^2y}{dx^2} + 3\left(\frac{dy}{dx}\right) = \left(e^y + \frac{dy}{dx}\right)^2$	(IV) Order = 2, Degree = Not defined

Choose the correct answer from the options given below:

CUET Mathematics 2025 21 May Shift 2 PYQs