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If the matrix [07−12−70−52a53b]\begin{bmatrix} 0 & 7 & -12 \\ -7 & 0 & -5 \\ 2a & 5 & 3b \end{bmatrix} is skew-symmetric, then the value of (4a+3b)(4a + 3b) is:

Solution

✅ Correct Option: 1

A matrix is skew-symmetric if AT=−AA^T = -A.

This means:

  • All diagonal elements must be 0
  • Each element at position (i,j)(i,j) equals the negative of the element at position (j,i)(j,i)

The matrix is [07−12−70−52a53b]\begin{bmatrix} 0 & 7 & -12 \\ -7 & 0 & -5 \\ 2a & 5 & 3b \end{bmatrix}

The diagonal elements are: 0,0,3b0, 0, 3b

Since all diagonal elements must be 0:

3b=03b = 0

b=0b = 0


For the elements at positions (1,3)(1,3) and (3,1)(3,1):

  • Position (1,3)=−12(1,3) = -12
  • Position (3,1)=2a(3,1) = 2a

The skew-symmetric property requires:

−12=−(2a)-12 = -(2a)

−12=−2a-12 = -2a

a=6a = 6


The value of (4a+3b)(4a + 3b):

4a+3b=4(6)+3(0)4a + 3b = 4(6) + 3(0)

=24+0= 24 + 0

=24= 24

Therefore, (4a+3b)=24(4a + 3b) = 24

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