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If A=[432−110]A = \begin{bmatrix} 4 & 3 \\ 2 & -1 \\ 1 & 0 \end{bmatrix} and BT=[12321−1]B^T = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 1 & -1 \end{bmatrix}, then A−BA - B is equal to

Solution

✅ Correct Option: 3

Given A=[432−110]A = \begin{bmatrix} 4 & 3 \\ 2 & -1 \\ 1 & 0 \end{bmatrix} and BT=[12321−1]B^T = \begin{bmatrix} 1 & 2 & 3 \\ 2 & 1 & -1 \end{bmatrix}.

Matrix AA is a 3×23 \times 2 matrix.

Matrix BTB^T is a 2×32 \times 3 matrix.


To find BB, transpose BTB^T by converting rows to columns.

Row 1 of BTB^T: [1,2,3][1, 2, 3] becomes Column 1 of BB

Row 2 of BTB^T: [2,1,−1][2, 1, -1] becomes Column 2 of BB

B=[12213−1]B = \begin{bmatrix} 1 & 2 \\ 2 & 1 \\ 3 & -1 \end{bmatrix}


Both AA and BB are 3×23 \times 2 matrices. Subtract corresponding elements:

A−B=[432−110]−[12213−1]A - B = \begin{bmatrix} 4 & 3 \\ 2 & -1 \\ 1 & 0 \end{bmatrix} - \begin{bmatrix} 1 & 2 \\ 2 & 1 \\ 3 & -1 \end{bmatrix}

A−B=[4−13−22−2−1−11−30−(−1)]A - B = \begin{bmatrix} 4-1 & 3-2 \\ 2-2 & -1-1 \\ 1-3 & 0-(-1) \end{bmatrix}

A−B=[310−2−21]A - B = \begin{bmatrix} 3 & 1 \\ 0 & -2 \\ -2 & 1 \end{bmatrix}

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