If the following data is obtained from a simple random sample:

6, 7, 9, 10, 11, 17

Then the point estimate of population standard deviation is:

Given data: 6, 7, 9, 10, 11, 17

The point estimate of population standard deviation uses the sample standard deviation formula with $(n-1)$ in the denominator.

---

Mean $= \dfrac{6 + 7 + 9 + 10 + 11 + 17}{6}$

Mean $= \dfrac{60}{6}$

Mean $= 10$

---

Calculate each deviation from the mean and square it:

Value	Deviation (Value - Mean)	Squared Deviation
6	$6 - 10 = -4$	$(-4)^2 = 16$
7	$7 - 10 = -3$	$(-3)^2 = 9$
9	$9 - 10 = -1$	$(-1)^2 = 1$
10	$10 - 10 = 0$	$(0)^2 = 0$
11	$11 - 10 = 1$	$(1)^2 = 1$
17	$17 - 10 = 7$	$(7)^2 = 49$

---

Sum of squared deviations $= 16 + 9 + 1 + 0 + 1 + 49$

Sum of squared deviations $= 76$

---

Sample Variance $s^2 = \dfrac{\text{Sum of squared deviations}}{n-1}$

$s^2 = \dfrac{76}{6-1}$

$s^2 = \dfrac{76}{5}$

$s^2 = 15.2$

---

Sample Standard Deviation $s = \sqrt{s^2}$

$s = \sqrt{15.2}$

$s = 3.898$

---

Therefore, the point estimate of population standard deviation is $3.898$.