A die is rolled in such a way that an even number is twice likely to occur as an odd number. If the die is rolled twice, then the mean of the number of perfect squares in two tosses is:

A box contains 3 red and 2 black balls and another box contains 2 red and 4 black balls. One box chosen at random. From the selected box one ball is drawn. The probability of getting a red ball is

The probability that exactly one of them complete the task on time is

For a biased die, the probabilities of outcomes are given as under.

$P(1)=P(2)=\dfrac{2}{10}, P(3)=P(5)=P(6)=\dfrac{1}{10}, P(4)=\dfrac{3}{10}$.

The die is thrown two times. Let A and B be events defined as

A is getting same number each time and

B is getting a total of 10 or more on die ,

then which one of the following is TRUE?

A random variable 'X' denotes the number of sixes obtained in three throws of a die. Then, the mean of the distribution is:-

A die is tossed 6 times and getting "1 or 5" is considered a success. The probability of getting at least one success in six tosses is:

There are 50 telephone lines in an exchange. The probability that any one of them will be busy is 0.1, then the probability that all the lines are busy?