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Let A be a non-singular matrix of order 3 and ∣A∣=15|A| = 15, then ∣adjA∣|adj A| is equal to

Solution

✅ Correct Option: 3

For any square matrix A of order nn:

∣adjA∣=∣A∣n−1|adj A| = |A|^{n-1}


Given:

Order of matrix A = 3

∣A∣=15|A| = 15


Applying the formula with n=3n = 3:

∣adjA∣=∣A∣n−1|adj A| = |A|^{n-1}

∣adjA∣=∣A∣3−1|adj A| = |A|^{3-1}

∣adjA∣=∣A∣2|adj A| = |A|^2


Substituting ∣A∣=15|A| = 15:

∣adjA∣=(15)2|adj A| = (15)^2

∣adjA∣=225|adj A| = 225

Therefore, ∣adjA∣=225|adj A| = 225.

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