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The function f(x)=6−6x−2x2f(x) = 6 - 6x - 2x^2

Solution

✅ Correct Option: 3

The function f(x)=6−6x−2x2f(x) = 6 - 6x - 2x^2

To find where the function increases or decreases, find the derivative:

f′(x)=−6−4xf'(x) = -6 - 4x


The critical point occurs when f′(x)=0f'(x) = 0:

−6−4x=0-6 - 4x = 0

−4x=6-4x = 6

x=−32x = -\frac{3}{2}


For x<−32x < -\frac{3}{2}, test x=−2x = -2:

f′(−2)=−6−4(−2)f'(-2) = -6 - 4(-2)

f′(−2)=−6+8f'(-2) = -6 + 8

f′(−2)=2>0f'(-2) = 2 > 0

The function is increasing when x<−32x < -\frac{3}{2}.


For x>−32x > -\frac{3}{2}, test x=0x = 0:

f′(0)=−6−4(0)f'(0) = -6 - 4(0)

f′(0)=−6<0f'(0) = -6 < 0

The function is decreasing when x>−32x > -\frac{3}{2}.


Therefore, the function is strictly decreasing for x>−32x > -\frac{3}{2}.

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