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The probability that it will rain on any particular day is 50%. The probability that it rains only on the first 4 days of the week is:

Solution

✅ Correct Option: 2

The question asks for the probability that it rains only on the first 4 days of the week.

This means it must rain on Monday, Tuesday, Wednesday, and Thursday, and must not rain on Friday, Saturday, and Sunday.


The probability of rain on any day is 12\frac{1}{2}.

The probability of no rain on any day is 12\frac{1}{2}.


Since each day's weather is independent, the probabilities are multiplied.

For the first 4 days (rain required):

Probability =12×12×12×12=(12)4= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \left(\frac{1}{2}\right)^4

For the remaining 3 days (no rain required):

Probability =12×12×12=(12)3= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \left(\frac{1}{2}\right)^3


Total Probability =(12)4×(12)3= \left(\frac{1}{2}\right)^4 \times \left(\frac{1}{2}\right)^3

=(12)7= \left(\frac{1}{2}\right)^7

=1128= \frac{1}{128}

Therefore, the probability that it rains only on the first 4 days of the week is 1128\frac{1}{128}.

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