The differential equation dy/dx + x/y = 0, represents the family of curves: Option 1: x^2 - y^2 = C Option 2: x/y = C Option 3: xy = C Option 4: x^2 + y^2 = C

The answer is 'x^2 + y^2 = C'. View full solution:

CUET Mathematics - The differential equation dy/dx + x/y = 0, represents the family of curves: | PYQs + Solutions

CUET Mathematics 2022 25 May Shift 1

Calculus

Easy

$x^2 - y^2 = C$

$\frac{x}{y} = C$

$xy = C$

$x^2 + y^2 = C$

✅ Correct Option: 4

Related questions:

26 May Shift 2

Match List-I with List-II

List-I	List-II
Differential Equations	Order and degree
(A) $ydx + x\log(y/x)dy - 2xdy = 0$	(I) Order : 2, degree:1
(B) $\left(\frac{d^3y}{dx^3}\right)^2 + 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^2$	(II) Order :1, degree:1
(C) $\frac{dy}{dx} + \log\left(\frac{dy}{dx}\right) + x = y$	(III) Order : 3, degree:2
(D) $\left(\frac{ds}{dt}\right)^4 + 2s\frac{d^2s}{dt^2} = 0$	(IV) Order : 1, degree: Not defined

Choose the correct answer from the options given below:

16 May Shift 1

The degree of the differential equation $\left(1-\left(\frac{d y}{d x}\right)^{2}\right)^{\frac{3}{2}}=k \frac{d^{2} y}{d x^{2}}$ is :

21 May Shift 1

A integrating factor of the differential equation $\frac{dy}{dx} + \frac{y}{x} = \frac{1}{x^2}$ , $(x > 0)$ is equal to