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The equation of the tangent, to the curve y=x2−2x−3y = x^2 - 2x - 3 which is perpendicular to the line x+2y+3=0x + 2y + 3 = 0, is

Solution

✅ Correct Option: 2

Slope of given line =−12= -\frac{1}{2}, so perpendicular slope =2= 2. Setting y′=2x−2=2y' = 2x - 2 = 2 gives x=2x = 2, y=4−4−3=−3y = 4-4-3 = -3. Tangent: y−(−3)=2(x−2)y - (-3) = 2(x-2), i.e. 2x−y=72x - y = 7.

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