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If the cost function C(x)C(x) of producing xx units of a commodity is given as C(x)=x3−60x2+13x+50C(x) = x^3 - 60x^2 + 13x + 50, then the level of output for which the marginal cost is minimum is

Solution

✅ Correct Option: 3

Marginal cost: MC=C′(x)=3x2−120x+13MC = C'(x) = 3x^2 - 120x + 13. To minimize: d(MC)dx=6x−120=0\frac{d(MC)}{dx} = 6x - 120 = 0, so x=20x = 20. Second derivative =6>0= 6 > 0 confirms minimum. Output =20= 20 units.

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