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Match List I with List II

LIST ILIST II
A. Maximum value of f(x)=−∣x+1∣+3f(x) = -\lvert x+1 \rvert + 3I. 6
B. Minimum value of f(x)=(2x−1)2+5f(x) = (2x-1)^2 + 5II. 5
C. Maximum value of f(x)=6−x2f(x) = 6 - x^2III. no maximum value
D. Maximum value of f(x)=x3+1f(x) = x^3 + 1IV. 3

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

A: −∣x+1∣+3-|x+1| + 3 is maximum when ∣x+1∣=0|x+1| = 0, value =3= 3 (IV).

B: (2x−1)2+5(2x-1)^2 + 5 is minimum when (2x−1)2=0(2x-1)^2 = 0, value =5= 5 (II).

C: 6−x26 - x^2 is maximum when x=0x = 0, value =6= 6 (I).

D: x3+1x^3 + 1 has no maximum (unbounded above) (III).

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