The feasible region of an LPP Max Z = 3x + 2y subject to x ≥ 0, y ≥ 0, x - 2y ≤ 3 is: Option 1: Bounded in first quadrant but has no solution Option 2: Unbounded in first quadrant but has a solution Option 3: Unbounded in first quadrant and has no solution Option 4: Bounded and has a solution x = 0, y = 0, Z = 0

The answer is 'Unbounded in first quadrant and has no solution'. View full solution:

CUET Mathematics - The feasible region of an LPP Max Z = 3x + 2y subject to x ≥ 0, y ≥ 0, x - 2y ≤ 3 is: | PYQs + Solutions

CUET Mathematics 2022 25 May Shift 1

Algebra

Medium

Bounded in first quadrant but has no solution

Unbounded in first quadrant but has a solution

Unbounded in first quadrant and has no solution

Bounded and has a solution $x = 0, y = 0, Z = 0$

✅ Correct Option: 3

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The objective function for a L.P.P. is $Z = 5x + 7y$ and the corner points of the bounded feasible region are (0, 0), (7, 0), (3, 4) and (0, 2), then the maximum value of Z occurs at

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If the corner points of bounded feasible region for an LPP are (0,2) (3,0) (6,0) (6,8) and (0, 5) then the minimum value of the objective function f=4x+6y occur at

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Consider the linear programming problem(LPP):

Minimize $Z = x + y$

$x + 2y \leq 4,$

$3x + y \geq 3,$

$4x + 3y \geq 6,$

$x, y \geq 0.$

Which of the following is correct for the above linear programming problem (LPP):

(A) The LPP has a bounded feasible region.

(B) The LPP has a unique optimal solution.

(D) The corner points of the feasible region are (3/2, 0), (3/5, 6/5), (2/5, 6/5) and (4, 0)

Choose the correct answer from the options given below:

CUET Mathematics 2022 25 May Shift 1 PYQs

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