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The point on the straight line 3x+4y=83x + 4y = 8, which is closest to the origin is:

Solution

✅ Correct Option: 2

The closest point is the foot of the perpendicular from the origin to 3x+4y−8=03x + 4y - 8 = 0. Using formula: x=0−3(−8)25=2425x = 0 - \frac{3(-8)}{25} = \frac{24}{25}, y=0−4(−8)25=3225y = 0 - \frac{4(-8)}{25} = \frac{32}{25}. Point: (2425,3225)\left(\frac{24}{25}, \frac{32}{25}\right).

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