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The longest side of a triangle is 4 times the shortest side and the third side is 3 cm shorter than the longest side. If the perimeter of the triangle is at least 69 cm, then the minimum length of the shortest side is:

Solution

✅ Correct Option: 4

Let shortest side =s= s. Longest =4s= 4s, third =4s−3= 4s - 3. Perimeter =s+4s+4s−3=9s−3≥69= s + 4s + 4s - 3 = 9s - 3 \geq 69, giving 9s≥729s \geq 72, so s≥8s \geq 8. Minimum shortest side =8= 8 cm.

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