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Match the LIST-I with LIST-II

LIST-I
Differential equation
LIST-II
Order and Degree
A.(dydx)2+3y(d2ydx2)=0\left(\dfrac{dy}{dx}\right)^2 + 3y\left(\dfrac{d^2y}{dx^2}\right) = 0I.1,11,1
B.1−(dydx)2=a(d2ydx2)1/3\sqrt{1-\left(\dfrac{dy}{dx}\right)^2} = a\left(\dfrac{d^2y}{dx^2}\right)^{1/3}II.1,21,2
C.y=dydx+5(dy/dx)y = \dfrac{dy}{dx} + \dfrac{5}{(dy/dx)}III.2,12,1
D.1−y2 dx+1−x2 dy=0\sqrt{1-y^2}\,dx + \sqrt{1-x^2}\,dy = 0IV.2,22,2

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

A: highest derivative d2ydx2\dfrac{d^2y}{dx^2} appears to power 1, so order 2, degree 1 (III).

B: cube then square to clear radicals, giving (1−(y′)2)3=a6(y′′)2(1-(y')^2)^3 = a^6(y'')^2, so order 2, degree 2 (IV).

C: multiply by y′y' to get yy′=(y′)2+5yy' = (y')^2+5, so order 1, degree 2 (II).

D: only first order differentials, degree 1 (I).

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