Skip to main contentSkip to solution

If the matrix A=[0x+y13z2x−y−20]A = \begin{bmatrix} 0 & x+y & 1 \\ 3 & z & 2 \\ x-y & -2 & 0 \end{bmatrix} is skew-symmetric, then :

Solution

✅ Correct Option: 3

Skew-symmetric requires diagonal =0= 0 and aij=−ajia_{ij} = -a_{ji}. So z=0z = 0. Also x+y=−3x+y = -3 (from a12=−a21a_{12}=-a_{21}) and 1=−(x−y)1 = -(x-y), i.e. x−y=−1x-y = -1. Solving: x=−2,y=−1,z=0x = -2, y = -1, z = 0.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question