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A shopkeeper has 10 litres of pure honey. He sells honey at the cost price of Rs. 300 per litre. After mixing some quantity of water in pure honey he sells the syrup of pure honey and water at Rs. 250 per litre. The quantity of water mixed in pure honey is

Solution

✅ Correct Option: 1

Cost of 10 L pure honey =10×300=3000= 10 \times 300 = 3000 Rs. Selling at 250 per litre, to recover cost: 250×(total volume)=3000250 \times \text{(total volume)} = 3000, so total volume =12= 12 L. Water added =12−10=2= 12 - 10 = 2 L.

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