The solution of the differentiable equation 2xdy/dx + y = 14x^3, x > 0, is Option 1: y = 2x^3 + c x^1/2 Option 2: y = x^3 + c x^1/2 Option 3: y = 2x^3 + c x^-1/2 Option 4: y = x^3 + c x^-1/2

The answer is 'y = 2x^3 + c x^-1/2'. View full solution:

CUET Mathematics - The solution of the differentiable equation 2xdy/dx + y = 14x^3, x > 0, is | PYQs + Solutions

CUET Mathematics 2022 25 May Shift 1

Calculus

Medium

$y = 2x^3 + c x^{\frac{1}{2}}$

$y = x^3 + c x^{\frac{1}{2}}$

$y = 2x^3 + c x^{-\frac{1}{2}}$

$y = x^3 + c x^{-\frac{1}{2}}$

✅ Correct Option: 3