General solution of the differential equation x(xdy - ydx) = y dx is :(where c is an arbitrary constant) Option 1: |1/x| = e^-y/x+c Option 2: |1/x| = e^y/x+c Option 3: |y/x| = e^-1/x+c Option 4: |y/x| = e^1/x+c

The answer is '|y/x| = e^-1/x+c'. View full solution:

CUET Mathematics - General solution of the differential equation x(xdy - ydx) = y dx is :(where c is an arbitrary constant) | PYQs + Solutions

CUET Mathematics 2026 26th May Shift 2

Calculus

Medium

common

$\left|\dfrac{1}{x}\right| = e^{\frac{-y}{x}+c}$

$\left|\dfrac{1}{x}\right| = e^{\frac{y}{x}+c}$

$\left|\dfrac{y}{x}\right| = e^{\frac{-1}{x}+c}$

$\left|\dfrac{y}{x}\right| = e^{\frac{1}{x}+c}$

✅ Correct Option: 3