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The range of the function f(x)=13−sin⁡4xf(x) = \frac{1}{3 - \sin 4x} is:

Solution

✅ Correct Option: 1

sin⁡4x∈[−1,1]\sin 4x \in [-1, 1], so 3−sin⁡4x∈[2,4]3 - \sin 4x \in [2, 4]. Therefore f(x)=13−sin⁡4x∈[14,12]f(x) = \frac{1}{3-\sin 4x} \in \left[\frac{1}{4}, \frac{1}{2}\right].

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