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In a box containing 100 bulbs, 10 are defective. Then the probability, that out of a sample of 5 bulbs none is defective, is:

Solution

✅ Correct Option: 3

Probability that one bulb is non-defective =90100=910= \frac{90}{100} = \frac{9}{10}. Treating selections as independent (binomial model), probability all 5 are non-defective =(910)5= \left(\frac{9}{10}\right)^5.

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