Skip to main contentSkip to solution

A coin is tossed 7 times. The probability of getting at least 4 heads is:

Solution

✅ Correct Option: 4

X∼Binomial(7,1/2)X \sim \text{Binomial}(7, 1/2). By symmetry of the distribution: P(X≥4)=P(X≤3)P(X \geq 4) = P(X \leq 3). Since these events are complementary and equal: each =12= \frac{1}{2}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question