If A = bmatrix & & 0 \\ - & & 0 \\ 0 & 0 & 1 bmatrix and B is a square matrix of order 3, then |AB| is equal to: Option 1: |B|^2 Option 2: |B| Option 3: ^2 |B| Option 4: ^2 |B|

The answer is '|B|'. View full solution:

CUET Mathematics - If A = bmatrix & & 0 \\ - & & 0 \\ 0 & 0 & 1 bmatrix and B is a square matrix of order 3, then |AB| is equal to: | PYQs + Solutions

CUET Mathematics 2022 25 May Shift 1

Algebra

Medium

$|B|^2$

$|B|$

$\sin^2\theta |B|$

$\cos^2\theta |B|$

✅ Correct Option: 2

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Match List-I with List-II

Let $A$ be any invertible square matrix. Then

List-I	List-II
(A) $A - A^T$	(I) $\vert A\vert A^{-1}$
(B) $A A^T$	(II) Skew-symmetric
(C) $\det (A^{-1})$	(III) Symmetric
(D) $\text{adj} A$	(IV) $[\det(A)]^{-1}$

Choose the correct answer from the options given below:

CUET Mathematics 2022 25 May Shift 1 PYQs

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