Q2:

Matrices & Determinants

Easy

Core

Let A and B be square matrices of order 3 and k is a constant. If ∣A∣≠0|A| \neq 0 and ∣B∣≠0|B| \neq 0, where ∣A∣|A| represents the determinant of A, then which of the following statements are true ? (where A' denotes the transpose of matrix A)

(A) (AB)−1=B−1A−1(AB)^{-1} = B^{-1} A^{-1}

(B) (A+B)′=A′×B′(A+B)' = A' \times B'

(C) (AB)′=A′B′(AB)' = A'B'

(D) ∣kA∣=k3∣A∣|kA| = k^3 |A|

(E) ∣A′∣=∣A∣|A'| = |A|

Choose the correct answer from the options given below :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 2

Q4:

Continuity & Differentiability

Easy

Core

If y=xxy = x^x, then value of dydx\frac{dy}{dx} at x=2x = 2 is :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 4

Q6:

Continuity & Differentiability

Medium

Core

A function f(x)f(x) is defined by :

f(x)={x+2,if x<0−x+2,if x>0f(x) = \begin{cases} x + 2, & \text{if } x < 0 \\ -x + 2, & \text{if } x > 0 \end{cases}

Which of the following is true ?

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 6

Q7:

Application of Integrals

Easy

Core

The area of the region bounded by the curve x=y2x = y^2 and the line x=4x = 4 is equal to :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 7

Q8:

Integrals

Easy

Core

∫01x2ex3 dx\int_{0}^{1} x^2 e^{x^3} \, dx is equal to :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 8

Q9:

Integrals

Medium

Core

If ddx(f(x))=5x4−4x5\frac{d}{dx}(f(x)) = 5x^4 - \frac{4}{x^5} such that f(1)=0f(1) = 0. Then f(2)−2f(12)f(2) - 2f\left(\frac{1}{2}\right) is equal to :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 9

Q10:

Integrals

Easy

Core

If f(x)={1−2x,x≤01+2x,x>0f(x) = \begin{cases} 1 - 2x, & x \leq 0 \\ 1 + 2x, & x > 0 \end{cases}, then ∫−11f(x) dx=\int_{-1}^{1} f(x) \, dx =

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 10

Q11:

Continuity & Differentiability

Easy

Core

If y=500e7x+600e−7xy = 500 e^{7x} + 600 e^{-7x} and d2ydx2=ky\frac{d^2 y}{dx^2} = ky, then the value of k is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 11

Q12:

Differential Equations

Easy

Core

The general solution of the differential equation dydx=ex+y\frac{dy}{dx} = e^{x+y}, is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 12

Q13:

Probability

Easy

Core

Let X be a discrete random variable and probability distribution X is

X−1-101
P(X)12\frac{1}{2}15\frac{1}{5}310\frac{3}{10}

Then E(X) is equal to :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 13

Q14:

Probability

Medium

Core

In Binomial distribution with parameters n=12n = 12 and p=13p = \frac{1}{3}, value of E(X2)+E(X)E(X^2) + E(X) is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 14

Q15:

Linear Programming

Easy

Core

The solution of LPP

max.(z) = 5x+3y5x + 3y subject to

2x+y≤62x + y \leq 6

x+y≤4x + y \leq 4

x≥0,y≥0x \geq 0, y \geq 0, is

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 15

Q16:

Relations & Functions

Easy

Core

The modulus function f:R→Rf : R \to R, given by f(x)=∣x∣f(x) = |x|, is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 16

Q17:

Relations & Functions

Easy

Core

Let L be the set of all lines in a plane and R be the relation in L defined as R={(l1,l2):l1 is perpendicular to l2, where l1,l2∈L}R = \{(l_1, l_2) : l_1 \text{ is perpendicular to } l_2, \text{ where } l_1, l_2 \in L\}. Choose the correct answer :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 17

Q18:

Matrices & Determinants

Easy

Core

Let A=(aij)A = (a_{ij}) and B=(bij)B = (b_{ij}) are square matrices of same order.

(A) The number of possible matrices of order 2×22 \times 2 with entries −1,0,1-1, 0, 1 is 81.

(B) A+A′A + A' is skew symmetric matrix

(C) A⋅A−1=0A \cdot A^{-1} = 0, ∣A∣≠0|A| \neq 0

(D) A is skew symmetric matrix if aij=−ajia_{ij} = -a_{ji} for all i,ji, j

(E) (AB)′=A′B′(AB)' = A'B'

Choose the correct answer from the options given below :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 18

Q19:

Matrices & Determinants

Medium

Core

Match List - I with List - II.

List - IList - II
(A)A=[6923]A = \begin{bmatrix} 6 & 9 \\ 2 & 3 \end{bmatrix}, B=[260798]B = \begin{bmatrix} 2 & 6 & 0 \\ 7 & 9 & 8 \end{bmatrix}, AB will be(I)[7511772353924]\begin{bmatrix} 75 & 117 & 72 \\ 35 & 39 & 24 \end{bmatrix}
(B)P=[8453017195]P = \begin{bmatrix} 8 & 45 & 30 \\ 17 & 19 & 5 \end{bmatrix}, Q=[67724283019]Q = \begin{bmatrix} 67 & 72 & 42 \\ 8 & 30 & 19 \end{bmatrix}, P+Q will be(II)[7511772253924]\begin{bmatrix} 75 & 117 & 72 \\ 25 & 39 & 24 \end{bmatrix}
(C)[854269734250]−[10−75−338326]\begin{bmatrix} 85 & 42 & 69 \\ 73 & 42 & 50 \end{bmatrix} - \begin{bmatrix} 10 & -75 & -3 \\ 38 & 3 & 26 \end{bmatrix}(III)[7511772254924]\begin{bmatrix} 75 & 117 & 72 \\ 25 & 49 & 24 \end{bmatrix}
(D)2[343630121820]+[75512113−16]2 \begin{bmatrix} 34 & 36 & 30 \\ 12 & 18 & 20 \end{bmatrix} + \begin{bmatrix} 7 & 55 & 12 \\ 1 & 13 & -16 \end{bmatrix}(IV)[7512772254924]\begin{bmatrix} 75 & 127 & 72 \\ 25 & 49 & 24 \end{bmatrix}

Choose the correct answer from the options given below :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 19

Q21:

Application of Integrals

Hard

Core

The area bounded by x=9−y2x = \sqrt{9 - y^2}, x−y+3=0x - y + 3 = 0 and x-axis is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 21

Q22:

Integrals

Easy

Core

∫1cos⁡2x(1+tan⁡x)3 dx=\int \frac{1}{\cos^2 x (1 + \tan x)^3} \, dx =

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 22

Q23:

Integrals

Medium

Core

∫x2+4(x2+3)(x2+5) dx=utan⁡−1(x3)+vtan⁡−1(x5)+c\int \frac{x^2 + 4}{(x^2 + 3)(x^2 + 5)} \, dx = u \tan^{-1}\left(\frac{x}{\sqrt{3}}\right) + v \tan^{-1}\left(\frac{x}{\sqrt{5}}\right) + c, where c is arbitrary constant, then value of 1u2+1v2\frac{1}{u^2} + \frac{1}{v^2} is equal to :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 23

Q24:

Application of Integrals

Medium

Core

The area bounded by the parabola y2=4axy^2 = 4ax and x2=4ayx^2 = 4ay is :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 24

Q25:

Integrals

Medium

Core

For a,b∈Ra, b \in R and a<ba < b, ∫abf(x)f(x)+f(a+b−x) dx=\int_{a}^{b} \frac{f(x)}{f(x) + f(a + b - x)} \, dx =

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 25

Q26:

Continuity & Differentiability

Medium

Core

If y=xsin⁡xy = x^{\sin x}, then value of x−sin⁡xdydx−cos⁡xlog⁡xx^{-\sin x} \frac{dy}{dx} - \cos x \log x is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 26

Q27:

Continuity & Differentiability

Medium

Core

f(x)=[x]f(x) = [x], where [ ][\,] represents greatest integer function.

(A) For 2≤x<32 \leq x < 3, [x]=3[x] = 3

(B) For 2≤x<32 \leq x < 3, [x]=2[x] = 2

(C) Right hand derivative of f at x=2x = 2 is not defined

(D) Left hand derivative of f at x=2x = 2 is zero

(E) f(x)f(x) is not differentiable at x=2x = 2

Choose the correct answer from the options given below :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 27

Q28:

Differential Equations

Medium

Core

If curve represented by differential equation xdydx+y=exx \frac{dy}{dx} + y = e^x passes through (1, 1), then y(−1)y(-1) is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 28

Q29:

Differential Equations

Medium

Core

If U(x)=x+1+x2U(x) = x + \sqrt{1 + x^2}, then solution of the differential equation dydx+1+y21+x2=0\frac{dy}{dx} + \sqrt{\frac{1 + y^2}{1 + x^2}} = 0, is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 29

Q30:

Differential Equations

Medium

Core

The differential equation representing family of curves y=e−2x(acos⁡x+bsin⁡x)y = e^{-2x}(a \cos x + b \sin x), where a and b are arbitrary constant, is :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 30

Q31:

3D Geometry

Medium

Core

Find the root of perpendicular from origin to the line x−13=y−2−2=z+13\frac{x - 1}{3} = \frac{y - 2}{-2} = \frac{z + 1}{3}.

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 31

Q33:

3D Geometry

Easy

Core

Equation of y-axis in space, in vector form is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 33

Q34:

Vector Algebra

Medium

Core

Match List - I with List - II.

List - I (Two given vector)List - II (Projection of a⃗\vec{a} on b⃗\vec{b})
(A)a⃗=i^−j^\vec{a} = \hat{i} - \hat{j}, b⃗=i^+j^\vec{b} = \hat{i} + \hat{j}(I)25\frac{2}{\sqrt{5}}
(B)a⃗=i^+j^\vec{a} = \hat{i} + \hat{j}, b⃗=2i^−k^\vec{b} = 2\hat{i} - \hat{k}(II)0
(C)a⃗=j^+k^\vec{a} = \hat{j} + \hat{k}, b⃗=i^+k^\vec{b} = \hat{i} + \hat{k}(III)2\sqrt{2}
(D)a⃗=2i^+3j^\vec{a} = 2\hat{i} + 3\hat{j}, b⃗=i^−k^\vec{b} = \hat{i} - \hat{k}(IV)12\frac{1}{\sqrt{2}}

Choose the correct answer from the options given below :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 34

Q35:

3D Geometry

Easy

Core

The angle between 2 planes 4x+8y+z−8=04x + 8y + z - 8 = 0 and y+z−4=0y + z - 4 = 0 is :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 35

Q36:

Vector Algebra

Easy

Core

The unit vector in the direction of the sum of vectors a⃗=2i^+2j^−5k^\vec{a} = 2\hat{i} + 2\hat{j} - 5\hat{k} and b⃗=2i^+j^+3k^\vec{b} = 2\hat{i} + \hat{j} + 3\hat{k} is :

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 36

Q37:

3D Geometry

Medium

Core

The equation of plane that contains line x−1−1=y+12=z−13\frac{x - 1}{-1} = \frac{y + 1}{2} = \frac{z - 1}{3} and also pass through point (0,1,0)(0, 1, 0) is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 37

Q38:

Linear Programming

Easy

Core

The corner points of the feasible region determined by inequalities of LPP are (4,10)(4, 10), (6,8)(6, 8) and (6,5)(6, 5). Let z=3x+4yz = 3x + 4y be the objective function. Then the sum of maximum value of z and minimum value of z is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 38

Q39:

Probability

Medium

Core

Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. The probability that it was drawn from Bag II is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 39

Q40:

Probability

Easy

Core

In Binomial distribution with parameters n=100n = 100 and p, Variance of distribution is maximum when p is equal to :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 40

Q41:

Probability

Easy

Core

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

The probability of a randomly chosen seed to germinate is :

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 41

Q42:

Probability

Easy

Core

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

The probability that seed will not germinate, given that the seed is of type A3A_3.

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 42

Q43:

Probability

Medium

Core

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

The probability that seed is of type A2A_2 given that seed germinate.

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 43

Q44:

Probability

Medium

Core

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

The probability that seed is not of type A1A_1, given that seed germinates.

Answer options
Option 2
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 44

Q45:

Probability

Medium

Core

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

A shopkeeper sells three types of flower seeds A1,A2,A3A_1, A_2, A_3. They are sold as a mixture where the proportions are 4 : 4 : 2 respectively. The germination rates of the three types of seeds are 45%, 60% and 35% respectively. Calculate the probability in the following cases.

The probability that seed is of type A1A_1 given that seed doesn't germinate.

Answer options
Option 4
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 45

Q46:

Application of Integrals

Easy

Core

Based on the following given information answer the question

Consider the function f(x)=x∣x∣f(x) = x|x|, x∈Rx \in R.

The region bounded by curve y=x∣x∣y = x|x|, x-axis and lines x=±1x = \pm 1 is best represented graphically by :

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 46

Q47:

Application of Integrals

Easy

Core

Based on the following given information answer the question

Consider the function f(x)=x∣x∣f(x) = x|x|, x∈Rx \in R.

The area of the region bounded by f(x)=x∣x∣f(x) = x|x| and x-axis from x=0x = 0 to x=4x = 4 is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 47

Q48:

Application of Integrals

Medium

Core

Based on the following given information answer the question

Consider the function f(x)=x∣x∣f(x) = x|x|, x∈Rx \in R.

The area of the region bounded by f(x)=x∣x∣f(x) = x|x|, x-axis and from x=−1x = -1 to x=1x = 1 is :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 48

Q49:

Application of Derivatives

Easy

Core

Based on the following given information answer the question

Consider the function f(x)=x∣x∣f(x) = x|x|, x∈Rx \in R.

The slope of the tangent drawn at the point whose x coordinates is 2 on the curve y=x∣x∣y = x|x|.

Answer options
Option 3
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 49

Q50:

Continuity & Differentiability

Medium

Core

Based on the following given information answer the question

Consider the function f(x)=x∣x∣f(x) = x|x|, x∈Rx \in R.

Consider the following statements for the curve f(x)=x∣x∣f(x) = x|x| and find that which of the following(s) are/is correct :

(A) f(x)=x∣x∣f(x) = x|x| is differentiable at x=0x = 0.

(B) f(x)=x∣x∣f(x) = x|x| is continuous at x=0x = 0 but not differentiable at x=0x = 0.

(C) f(x)=x∣x∣f(x) = x|x| has point of infection at x=0x = 0.

(D) f(x)=x∣x∣f(x) = x|x| is symmetrical about y-axis.

Choose the correct answer from the options given below :

Answer options
Option 1
Correct Answer
Explanation for 2022: 7 Aug Shift 2 MAT question 50

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