The derivative of (^-1 e^2x) with respect to x is: Option 1: 2e^2x (^-1 e^2x)1 + e^4x Option 2: 2e^2x (^-1 e^2x)1 + e^4x Option 3: 2e^2x (^-1 e^2x)1 + e^x^2 Option 4: 2e^2x (^-1 e^2x)1 + e^2x

The answer is '2e^2x (^-1 e^2x)1 + e^4x'. View full solution:

CUET Mathematics - The derivative of (^-1 e^2x) with respect to x is: | PYQs + Solutions

CUET Mathematics 2022 25 May Shift 1

Calculus

Medium

$\frac{2e^{2x} \sin(\tan^{-1} e^{2x})}{1 + e^{4x}}$

$\frac{2e^{2x} \cos(\tan^{-1} e^{2x})}{1 + e^{4x}}$

$\frac{2e^{2x} \sin(\tan^{-1} e^{2x})}{1 + e^{x^2}}$

$\frac{2e^{2x} \cos(\tan^{-1} e^{2x})}{1 + e^{2x}}$

✅ Correct Option: 2