Algebra

Probability

Easy

common

In a meeting, 70% of the members favour and 30% oppose a certain proposal. A member is selected at random and we take X = 0 if he opposed, and X = 1 if he is in favour. Then, E (X) is :

$\frac{7}{10}$

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{7}{11}$

✅ Correct Option: 1

$P(X=0) = 0.3$ and $P(X=1) = 0.7$ . So $E(X) = 0 \cdot 0.3 + 1 \cdot 0.7 = 0.7 = \frac{7}{10}$ .

2026: 15 May Shift 1

Let A and B are two events associated to a random experiment, then

Match the LIST-I with LIST-II

LIST-I	LIST-II
A. $P(A \cap B) + P(A \cap \overline{B})$	I. $P(A \cup B)$
B. $P(A \cap B) + P(\overline{A} \cap B)$	II. $P(A) + P(B)$
C. $P(A \cap B) + P(\overline{A} \cap B) + P(A \cap \overline{B})$	III. $P(A)$
D. $P(A \cup B) + P(A \cap B)$	IV. $P(B)$

Choose the correct answer from the options given below:

2025: 3 June Shift 1

If A and B are independent events, then which of the following is not true?

2022: 17 Aug Shift 2

A letter is expected to come either from city 'SURAT' or from city 'RAMPUR' through post office. If on the way, envelope containing the letter is damaged and only two consecutive alphabets RA are visible on it, then the probability that letter comes from the city 'SURAT' is :

2022: 30 Aug Shift 1

The probability that the task is completed on time by none of them is

2023: 30 May Shift 3

If the probability distribution of a random variable X is as given below :

X	-1	0	1	2	3
P(X)	K	$\frac{1}{5}$	2K	$\frac{3}{10}$	K

Then the value of K is :

2025: 13 May Shift 2

A random variable X has the following probability distribution

X	0	1	2	3	4	5	6	7	8
P(X)	a	3a	5a	7a	9a	11a	13a	15a	17a

Then the values of 'a' and P(0 < X < 5) respectively are

In a meeting, 70% of the members favour and 30% oppose a certain proposal. A member is selected at random and we take X = 0 if he opposed, and X = 1 if he is in favour. Then, E (X) is :

Solution

Related questions:

Keyboard Shortcuts

CUET Mathematics Past Year Questions (Topic-Wise)