The area enclosed by the ellipse $\frac{x^2}{9^2} + \frac{y^2}{6^2} = 1$ is:

Area bounded by the curves $y = x|x|$, $x = -1$, $x = 1$ is

The area of the region bounded by the curves $y = x^2 + 2$, $y = x$, $x = 0$ and $x = 2$ is

The area bounded by the curve defined by $x = 2\cos\theta$ and $y = 3\sin\theta$; is [where $\theta$ is a parameter]

The area of the region bounded by the curve $x = y^2$ and the line $x = 4$ is equal to :

The area (in square units) bounded by the curve $y = x^2|x|$, x-axis and the lines $x=-2$ and $x=2$, is

The area enclosed by the curve $y^2 = 4ax$ and its latus-rectum is