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Match List I with List II.

List IList II
A. d2ydx2+dydx=0\frac{d^2y}{dx^2} + \frac{dy}{dx} = 0I. order 3, degree 1
B. (d2ydx2)2=0\left(\frac{d^2y}{dx^2}\right)^2 = 0II. order 2, degree 2
C. d3ydx3+d2ydx2+y=0\frac{d^3y}{dx^3} + \frac{d^2y}{dx^2} + y = 0III. order 2, degree 1
D. sin⁡(dydx)+5y=0\sin\left(\frac{dy}{dx}\right) + 5y = 0IV. order 1, degree is not defined

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

A: order 2, degree 1 (III). B: order 2, degree 2 (II). C: order 3, degree 1 (I). D: trigonometric function of derivative, so order 1, degree not defined (IV). So A-III, B-II, C-I, D-IV.

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