Skip to main contentSkip to solution

If x=3t2x = 3t^2 and y=ty = \sqrt{t}, then the value of d2ydx2\frac{d^2y}{dx^2} is

Solution

✅ Correct Option: 3

Here dydx=1/(2t)6t=112t−3/2\frac{dy}{dx}=\frac{1/(2\sqrt t)}{6t}=\frac{1}{12}t^{-3/2}. Differentiating with respect to tt gives −18t−5/2-\frac{1}{8}t^{-5/2}, and dividing by dxdt=6t\frac{dx}{dt}=6t gives −148t−7/2=−148t3t-\frac{1}{48}t^{-7/2}=-\frac{1}{48t^3\sqrt t}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question