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If m and n are the order and degree of the differential equation 9d3ydx3={1+(dydx)2}5/29\frac{d^3y}{dx^3} = \left\{1 + \left(\frac{dy}{dx}\right)^2\right\}^{5/2}, then the value of 2m+3n2m+3n is equal to

Solution

✅ Correct Option: 2

Squaring both sides clears the fractional power, giving 81(d3ydx3)2={1+(dydx)2}581\left(\frac{d^3y}{dx^3}\right)^2=\left\{1+\left(\frac{dy}{dx}\right)^2\right\}^5. So the order is m=3m=3 and the degree is n=2n=2, making 2m+3n=6+6=122m+3n=6+6=12.

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