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The area (in sq. units) of region bounded by the curves y2=4xy^2 = 4x and y=xy = x is:

Solution

✅ Correct Option: 2

The curves meet where x2=4xx^2=4x, that is at (0,0)(0,0) and (4,4)(4,4). The area is ∫04(2x−x)dx=43(8)−8=323−8=83\int_0^4\left(2\sqrt x-x\right)dx=\frac{4}{3}(8)-8=\frac{32}{3}-8=\frac{8}{3}.

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