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Area bounded by the curves y=3x,y=xy = 3^x, y = x and x=1,x=2x = 1, x = 2 is:

Solution

✅ Correct Option: 1

On [1,2][1,2] the exponential lies above the line, so the area is ∫12(3x−x) dx=[3xlog⁡e3−x22]12=9−3log⁡e3−(2−12)=6log⁡e3−32\int_1^2(3^x-x)\,dx=\left[\frac{3^x}{\log_e 3}-\frac{x^2}{2}\right]_1^2=\frac{9-3}{\log_e 3}-\left(2-\frac{1}{2}\right)=\frac{6}{\log_e 3}-\frac{3}{2}.

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