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Three pipes A, B and C can fill a tank together in 8 hours. After working at it together for 2 hours, B is closed and A and C can fill the remaining part in 9 hours. The time in which B alone can fill the tank is :

Solution

✅ Correct Option: 2

The combined rate is 18\frac{1}{8} per hour, so two hours fill 14\frac{1}{4}. The remaining 34\frac{3}{4} takes A and C nine hours, so their rate is 112\frac{1}{12}. Hence B's rate is 18−112=124\frac{1}{8}-\frac{1}{12}=\frac{1}{24}, giving 24 hours alone.

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