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∫14{x}[x]dx\int_1^4 \frac{\{x\}}{[x]} dx is equal to

[Where {x}\{x\} = fractional part function and [x][x] = greatest integer function]

Solution

✅ Correct Option: 2

Split at the integers. On [1,2)[1,2) the integral is ∫12(x−1) dx=12\int_1^2 (x-1)\,dx=\frac{1}{2}; on [2,3)[2,3) it is 12⋅12=14\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}; on [3,4)[3,4) it is 13⋅12=16\frac{1}{3}\cdot\frac{1}{2}=\frac{1}{6}. The total is 1112\frac{11}{12}.

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