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The general solution of the given differential equation dy+(2y−e−2x)dx=0dy + (2y - e^{-2x})dx = 0, is:

[where c is an arbitrary constant]

Solution

✅ Correct Option: 4

Rewrite as dydx+2y=e−2x\frac{dy}{dx}+2y=e^{-2x}, a linear equation with integrating factor e2xe^{2x}. Then ddx(e2xy)=e2xe−2x=1\frac{d}{dx}\left(e^{2x}y\right)=e^{2x}e^{-2x}=1, so e2xy=x+ce^{2x}y=x+c.

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