The general solution of the given differential equation dy + (2y - e^-2x)dx = 0, is: [where c is an arbitrary constant] Option 1: 2e^2xy = x + c Option 2: e^2x + y = x + c Option 3: e^-2xy = x + c Option 4: e^2xy = x + c

The answer is 'e^2xy = x + c'. View full solution:

CUET Mathematics - The general solution of the given differential equation dy + (2y - e^-2x)dx = 0, is: [where c is an arbitrary constant] | PYQs + Solutions

CUET Mathematics 2026 19th May Shift 2

Calculus

Medium

core

$2e^{2x}y = x + c$

$e^{2x} + y = x + c$

$e^{-2x}y = x + c$

$e^{2x}y = x + c$

✅ Correct Option: 4

Related questions:

4 Aug Shift 1

Match List I with List II

List I	List II : Order and degree respectively
A. $\frac{dy}{dx} - (x^2+3) = 0$	I. 2 and 1
B. $2x^2 \frac{d^2y}{dx^2} - 3\frac{dy}{dx} + y = 0$	II. 2 and 3
C. $y''' + y^2 + e^{y'} = 0$	III. 1 and 1
D. $\left(\frac{ds}{dt}\right)^4 + 3s\left(\frac{d^2s}{dt^2}\right)^3 = 0$	IV. 3 and not defined

Choose the correct answer from the options given below:

3 June Shift 2

The sum of the order and degree of the differential equation representing the family of curves $y = mx + m^4$ , where m is arbitrary constant, is

22 May Shift 3

Integerating factor of $(x \log_e x) \frac{dy}{dx} + y = 2 \log_e x$ is :