If A and B are two square matrices of order 'n', where AB ≠ BA, then Option 1: (A+B)^2 = A^2 + 2AB + B^2 Option 2: (A+B)^2 = A^2 + 2BA + B^2 Option 3: (A+B)^2 = A^2 + AB + BA + B^2 Option 4: A^2 - B^2 = (A+B)(A-B)

The answer is '(A+B)^2 = A^2 + AB + BA + B^2'. View full solution:

CUET Mathematics - If A and B are two square matrices of order 'n', where AB ≠ BA, then | PYQs + Solutions

CUET Mathematics 2026 19th May Shift 2

Algebra

Easy

common

$(A+B)^2 = A^2 + 2AB + B^2$

$(A+B)^2 = A^2 + 2BA + B^2$

$(A+B)^2 = A^2 + AB + BA + B^2$

$A^2 - B^2 = (A+B)(A-B)$

✅ Correct Option: 3