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If A and B are two square matrices of order 'n', where AB≠BAAB \neq BA, then

Solution

✅ Correct Option: 3

Expanding, (A+B)2=(A+B)(A+B)=A2+AB+BA+B2(A+B)^2=(A+B)(A+B)=A^2+AB+BA+B^2. Since matrix multiplication is not commutative here, ABAB and BABA cannot be merged into 2AB2AB, and (A+B)(A−B)(A+B)(A-B) is not A2−B2A^2-B^2.

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