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For the constriants x+y≤60x + y \le 60, 5x+y≤1005x + y \le 100 and x≥0,y≥0x \ge 0, y \ge 0, the feasible region is:

Figure for CUET Mathematics 2026 19 May Shift 2 question 21 (Algebra)

Solution

✅ Correct Option: 3

The two boundary lines meet at (10,50)(10,50). Since both inequalities are satisfied at the origin, the feasible region is the quadrilateral with vertices (0,0)(0,0), (20,0)(20,0), (10,50)(10,50) and (0,60)(0,60), that is the origin-containing region marked R.

Note: The figure is not reproduced here, so we have identified the region by its vertices rather than by the printed label.

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