For the constriants , and , the feasible region is:

For the constriants , and , the feasible region is:
Solution
✅ Correct Option: 3
The two boundary lines meet at . Since both inequalities are satisfied at the origin, the feasible region is the quadrilateral with vertices , , and , that is the origin-containing region marked R.
Note: The figure is not reproduced here, so we have identified the region by its vertices rather than by the printed label.
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