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If A is a square matrix such that A2=IA^2 = I, then (A+I)3+(A−I)3−7A(A+I)^3 + (A-I)^3 - 7A is equal to

Solution

✅ Correct Option: 1

Since A2=IA^2=I, also A3=AA^3=A. Then (A+I)3=A3+3A2+3A+I=4A+4I(A+I)^3=A^3+3A^2+3A+I=4A+4I and (A−I)3=A3−3A2+3A−I=4A−4I(A-I)^3=A^3-3A^2+3A-I=4A-4I. Their sum is 8A8A, so the expression equals 8A−7A=A8A-7A=A.

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