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If x∈Nx \in N(Set of Natural Numbers) and ∣x+3−2−3x2x∣=8\begin{vmatrix} x+3 & -2 \\ -3x & 2x \end{vmatrix} = 8, then the value of xx is

Solution

✅ Correct Option: 2

The determinant is 2x(x+3)−(−2)(−3x)=2x2+6x−6x=2x22x(x+3)-(-2)(-3x)=2x^2+6x-6x=2x^2. Setting 2x2=82x^2=8 gives x=±2x=\pm 2, and since xx is a natural number, x=2x=2.

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