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For the function f(x)=−2∣log⁡e∣x∣∣f(x) = -2|\log_e|x||, which of the following is true?

Solution

✅ Correct Option: 1

For x>1x>1 we have log⁡ex>0\log_e x>0, so f(x)=−2log⁡exf(x)=-2\log_e x, which is smooth there. Also f(5)=−2log⁡e5<0f(5)=-2\log_e 5<0; the modulus creates a corner at x=1x=1, so differentiability fails there; and ff is undefined at x=0x=0.

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