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A car hire firm has two cars, which is hire out day by day. The number of demands for cars on each day is distributed as a Poisson distribution with mean 1.5. Then which of the following is/are TRUE? (use e−1.5=0.2231e^{-1.5} = 0.2231)

A. The probability of days when no car is required is 0.2231

B. The probability of days when some demand is refused is 0.1913

C. The probability of days when no car is required is 0.1913

D. The probability of days when some demand is refused is 0.2231

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

With λ=1.5\lambda=1.5, P(0)=e−1.5=0.2231P(0)=e^{-1.5}=0.2231, so A is true. Demand is refused when more than two cars are wanted: 1−e−1.5(1+1.5+1.125)=1−0.8087=0.19131-e^{-1.5}(1+1.5+1.125)=1-0.8087=0.1913, so B is true as well.

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