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The value of ∣log⁡3512log⁡43log⁡38log⁡49∣\begin{vmatrix} \log_3 512 & \log_4 3 \\ \log_3 8 & \log_4 9 \end{vmatrix} is:

Solution

✅ Correct Option: 1

Here log⁡3512=9log⁡32\log_3 512=9\log_3 2, log⁡38=3log⁡32\log_3 8=3\log_3 2, log⁡43=log⁡232\log_4 3=\frac{\log_2 3}{2} and log⁡49=log⁡23\log_4 9=\log_2 3. Since log⁡32⋅log⁡23=1\log_3 2\cdot\log_2 3=1, the determinant is 9−32=1529-\frac{3}{2}=\frac{15}{2}.

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