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The integral I=∫(1+log⁡ex)3xdxI = \int \frac{(1+\log_e x)^3}{x} dx is equal to

Solution

✅ Correct Option: 3

Substitute t=1+log⁡ext=1+\log_e x, so dt=dxxdt=\frac{dx}{x}. The integral becomes ∫t3 dt=t44+C=(1+log⁡ex)44+C\int t^3\,dt=\frac{t^4}{4}+C=\frac{(1+\log_e x)^4}{4}+C.

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