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Let f(x)=x3−3axf(x) = x^3 - 3ax, where a>0a > 0, then the values for which f(x)f(x) is decreasing, are

Solution

✅ Correct Option: 2

Here f′(x)=3x2−3a=3(x2−a)f'(x)=3x^2-3a=3(x^2-a), which is negative precisely when x2<ax^2<a. Since a>0a>0, this means −a<x<a-\sqrt a<x<\sqrt a.

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