CUET Mathematics - If A and B are invertible matrices of the same order, then, Match List-I with List-II | LIST-I | LIST-II | |---|---| | A. A^T | I. B^-1A^-1 | | B. A(adj A) | II. adj A | | C. A^-1 A | III. (adj A)A | | D. (AB)^-1 | IV. A | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 19th May Shift 2

Algebra

Medium

applied

A-I, B-II, C-IV, D-III

A-IV, B-III, C-II, D-I

A-IV, B-III, C-I, D-II

A-IV, B-II, C-III, D-I

✅ Correct Option: 2

Related questions:

30th May Shift 2

A is a square matrix of order 3 x 3, then

Match List-I with List-II

List-I	List-II
(A) $\left\vert \text{adj}A \right\vert$	(I) $\dfrac{1}{\left\vert A \right\vert}$
(B) $\left\vert A^{-1} \right\vert$	(II) $\left\vert A \right\vert^{4}$
(C) $\left\vert A.\text{adj}A \right\vert$	(III) $\left\vert A \right\vert^{3}$
(D) $\left\vert \text{adj}(\text{adj}A) \right\vert$	(IV) $\left\vert A \right\vert^{2}$

Choose the correct answer from the options given below:

22nd May Shift 2

Match List-I with List-II

List-I	List-II
(A) If $A=\begin{bmatrix}2 & -5\\3 & 4\end{bmatrix}$ , then adj A =	(I) $\begin{bmatrix}4 & -5\\-2 & -3\end{bmatrix}$
(B) If $A=\begin{bmatrix}2 & 3\\5 & -2\end{bmatrix}$ , then $A^{-1}=$	(II) $\begin{bmatrix}\frac{1}{17} & \frac{-5}{17}\\\frac{3}{17} & \frac{2}{17}\end{bmatrix}$
(C) If $A=\begin{bmatrix}-3 & 5\\2 & 4\end{bmatrix}$ , then adj A =	(III) $\begin{bmatrix}4 & 5\\-3 & 2\end{bmatrix}$
(D) If $A=\begin{bmatrix}2 & 5\\-3 & 1\end{bmatrix}$ , then $A^{-1}=$	(IV) $\begin{bmatrix}\frac{2}{19} & \frac{3}{19}\\\frac{5}{19} & \frac{-2}{19}\end{bmatrix}$

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21st May Shift 2

The value of $\begin{vmatrix}2 & 3 & 4\\5 & 6 & 8\\6x & 9x & 12x\end{vmatrix}$ is

CUET Mathematics 2026 19th May Shift 2 PYQs