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∫log⁡x−3(log⁡x)4dx\int \frac{\log x - 3}{(\log x)^4} dx is equal to

(where C is an arbitrary constant and log⁡ex=log⁡x\log_e x = \log x)

Solution

✅ Correct Option: 2

Differentiating x(log⁡x)3\frac{x}{(\log x)^3} by the quotient rule gives (log⁡x)3−3(log⁡x)2(log⁡x)6=log⁡x−3(log⁡x)4\frac{(\log x)^3-3(\log x)^2}{(\log x)^6}=\frac{\log x-3}{(\log x)^4}, exactly the integrand. Hence the integral is x(log⁡x)3+C\frac{x}{(\log x)^3}+C.

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