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If CijC_{ij} represents the cofactor of element aija_{ij} of the matrix A=[2−13120415]A = \begin{bmatrix} 2 & -1 & 3 \\ 1 & 2 & 0 \\ 4 & 1 & 5 \end{bmatrix} then the value of C23+C31−C22C_{23} + C_{31} - C_{22} is

Solution

✅ Correct Option: 3

The cofactor CijC_{ij} is given by (−1)i+jMij(-1)^{i+j} M_{ij}, where MijM_{ij} is the determinant of the submatrix after removing the ii-th row and jj-th column.

The matrix is:

A=[2−13120415]A = \begin{bmatrix} 2 & -1 & 3 \\ 1 & 2 & 0 \\ 4 & 1 & 5 \end{bmatrix}


C23=(−1)2+3∣2−141∣C_{23} = (-1)^{2+3} \begin{vmatrix} 2 & -1 \\ 4 & 1 \end{vmatrix}

C23=−1(2(1)−(−1)(4))C_{23} = -1(2(1) - (-1)(4))

C23=−1(2+4)C_{23} = -1(2 + 4)

C23=−6C_{23} = -6


C31=(−1)3+1∣−1320∣C_{31} = (-1)^{3+1} \begin{vmatrix} -1 & 3 \\ 2 & 0 \end{vmatrix}

C31=1((−1)(0)−(3)(2))C_{31} = 1((-1)(0) - (3)(2))

C31=1(0−6)C_{31} = 1(0 - 6)

C31=−6C_{31} = -6


C22=(−1)2+2∣2345∣C_{22} = (-1)^{2+2} \begin{vmatrix} 2 & 3 \\ 4 & 5 \end{vmatrix}

C22=1(2(5)−(3)(4))C_{22} = 1(2(5) - (3)(4))

C22=1(10−12)C_{22} = 1(10 - 12)

C22=−2C_{22} = -2


C23+C31−C22=−6+(−6)−(−2)C_{23} + C_{31} - C_{22} = -6 + (-6) - (-2)

=−6−6+2= -6 - 6 + 2

=−10= -10

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